2nd pull. I've gotta question; so when I shake the HCL water with the xylene, am I supposed to aim to have the water slightly acidic? And the number of drops of HCL needed to achieve this will vary depending on how much mescaline is present? From what I understand, the HCL and mescaline freebase combine and create mescaline hydrochloride salt, correct? Sorry guys, I'm a chemistry noob. I never took chem in high school cause I dropped out. Although I did do very well in the organic chem 101 course that I took
You want your the pH of your salting solution to be 4 lower than mescaline's pKa of 9.5, so around 5.5. Most people shoot for between 4-5 from what I recall. Lower pH tends to yield browner product as other compounds with lower pKas are salted out
As that acid reacts (I can draw this reaction for you if you want) with the mescaline freebase to form the salt it will no longer be present in the water in the way that pH meters & indicators detect, so the pH of your solution will go up. Yes, the amount of acid needed to react all the mescaline will vary based on the amount present, so what some people do is measure the pH of the acid layer after salting. If the pH is 7 or lower, they evaporate to attain the salt. If the pH is higher than 7 they add another couple drops of acid, mix the solutions, and measure again.
Never apologize for asking questions. Getting them answered is how we learn, and getting them answered on the open boards helps other people learn too! Did all that rambling up there make sense? [EDIT]That's some more good looking 2nd pull product too. Definitely back off on the acid a little bit for the 3rd & see what you get. [/EDIT]
Edited by Phineas_Carmichael, 26 May 2021 - 06:03 PM.